Investigate the conditions under which a functor's right derived functor preserves a complex's structure in the derived category | Step-by-Step Solution
Problem
Invariance under derived functor: Given an abelian category C, derived category D(C), and a left exact functor F, determine if RHom(F,C) ≅ C when F preserves homology
🎯 What You'll Learn
- Understand derived functor preservation
- Analyze complex morphism invariance
- Explore advanced category theory concepts
Prerequisites: Abelian category theory, Derived functors, Homological algebra
💡 Quick Summary
This is a beautiful question about derived functors and homological algebra! You're exploring when applying a derived functor essentially leaves a complex unchanged, which connects to some fundamental ideas about how "well-behaved" functors interact with homological structure. Here's what I'd encourage you to think about: what does it mean for a functor to "preserve homology," and how might this relate to what derived functors are designed to accomplish in the first place? Consider why we create derived functors - they're meant to "fix" functors that don't behave nicely with exact sequences, so what happens when we start with a functor that already behaves well? I'd suggest reviewing the relationship between exact functors and their derived versions, and think about whether there might be some redundancy when a functor already preserves the homological information we care about. You've got the right instincts to tackle this - trust your understanding of what derived functors are trying to achieve!
Step-by-Step Explanation
TinyProf's Guide to Derived Functor Invariance
What We're Solving: We need to investigate whether the right derived functor RHom(F,C) is isomorphic to a complex C when we have a left exact functor F that preserves homology. This is asking about a fundamental invariance property in homological algebra!
The Approach: This problem touches on some deep concepts in category theory and homological algebra. We're essentially asking: "When does applying a derived functor leave our complex essentially unchanged?"
Step-by-Step Solution:
Step 1: Clarify the Setup We have:
- An abelian category C (think of this as a nice setting where we can do homological algebra)
- D(C) is the derived category (where we work with complexes up to quasi-isomorphism)
- F is a left exact functor (preserves finite limits and exact sequences on the left)
- The condition "F preserves homology" means F takes quasi-isomorphic complexes to quasi-isomorphic complexes
- RF(C) ≅ C (applying the right derived functor of F to complex C)
- Or RHom(A,C) for some object A related to F
If F preserves homology AND we're working in the derived category, then F already captures the "derived" information without needing to derive it further!
Step 4: The Homology Preservation Condition When F preserves homology:
- F takes exact sequences to exact sequences (up to quasi-isomorphism)
- The derived functor RF essentially becomes F itself on the level of D(C)
- This is because F is already "doing the job" that the derived functor RF was designed to do
More precisely: If F preserves homology, then the natural morphism F(C) → RF(C) is a quasi-isomorphism, giving us RF(C) ≅ F(C) ≅ C in D(C) under appropriate conditions.
Memory Tip: Think of it this way: "If F already preserves homology, then deriving F doesn't add new information - it just confirms what F was already doing correctly!" The derived functor becomes redundant when the original functor already behaves well with respect to homology.
Great question! This touches on some beautiful connections between functors and their derived versions. The key insight is that when a functor already "behaves well" (preserves homology), the derived version doesn't need to "fix" anything - they essentially agree!
⚠️ Common Mistakes to Avoid
- Misinterpreting functor preservation conditions
- Confusing left and right derived functors
- Overlooking homology constraints
This explanation was generated by AI. While we work hard to be accurate, mistakes can happen! Always double-check important answers with your teacher or textbook.

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📷 Problem detected:
Solve: 2x + 5 = 13
Step 1:
Subtract 5 from both sides...
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