Demonstrate that a set of four subset elements forms a Klein four-group using symmetric difference operation | Step-by-Step Solution
Problem
Prove that a set V composed of subsets of a two-element set X is a Klein four-group using the symmetric difference operation (ā)
šÆ What You'll Learn
- Understand Klein four-group properties
- Apply symmetric difference operation
- Verify group axioms
Prerequisites: Set theory basics, Group axioms understanding, Symmetric difference definition
š” Quick Summary
Hi there! I see you're working on proving that a collection of subsets forms a Klein four-group under symmetric difference - this is a really beautiful connection between set theory and abstract algebra! To get started, think about what you need to show: first, that you have a group (which means checking the four group axioms), and second, that it has the special Klein four-group property. What do you know about symmetric difference as an operation, and can you list out all the subsets of a two-element set to see what elements you're working with? Consider starting by creating an operation table to check closure, and remember that for something to be a Klein four-group, every non-identity element should have order 2. You've got the right instincts to tackle this step by step - once you identify your four elements and understand how symmetric difference works, the group properties will start to emerge naturally!
Step-by-Step Explanation
What We're Solving:
We need to prove that when we take all possible subsets of a two-element set and use the symmetric difference operation (ā), we get a Klein four-group. This is a beautiful example of how familiar set operations can create important algebraic structures!The Approach:
To prove something is a Klein four-group, we need to show it satisfies the group axioms AND has the special Klein four-group property. Here's our strategy:- 1. Identify our set X and find all its subsets
- 2. Define our operation (symmetric difference ā)
- 3. Verify the four group axioms: closure, associativity, identity, and inverses
- 4. Show it's specifically a Klein four-group: every non-identity element has order 2
Step-by-Step Solution:
Step 1: Set up our elements Let X = {a, b} (our two-element set) Then V = {ā , {a}, {b}, {a,b}} (all possible subsets of X)
Step 2: Understand symmetric difference (ā) For any two sets A and B: A ā B = (A āŖ B) - (A ā© B) In other words, A ā B contains elements that are in exactly one of A or B, but not both.
Step 3: Verify closure We need to check that A ā B is always in V when A, B ā V. Create a operation table:
- ā ā ā = ā ā
- ā ā {a} = {a} ā
- {a} ā {b} = {a,b} ā
- {a} ā {a,b} = {b} ā
Step 4: Check associativity Symmetric difference is always associative for sets. You can verify this with the definition or use the fact that ā corresponds to addition in ā¤ā Ć ā¤ā.
Step 5: Find the identity element The empty set ā is our identity because A ā ā = A for any set A.
Step 6: Verify inverses Each element is its own inverse!
- ā ā ā = ā ā
- {a} ā {a} = ā ā
- {b} ā {b} = ā ā
- {a,b} ā {a,b} = ā ā
The Answer:
Yes! V with the symmetric difference operation forms a Klein four-group (Vā). It satisfies all group axioms, has 4 elements, is abelian, and every non-identity element has order 2. This group is isomorphic to ā¤ā Ć ā¤ā.Memory Tip:
Remember "Klein = Clean slate twice"! In a Klein four-group, doing any operation twice with the same element gets you back to the identity (like erasing on a clean slate). Also, the symmetric difference visually shows you what's "different" between two sets - perfect for a group where everything undoes itself!The beauty here is seeing how simple set operations create elegant algebraic structures. You've just connected basic set theory with abstract algebra! š
ā ļø Common Mistakes to Avoid
- Misunderstanding symmetric difference
- Failing to verify all group axioms
- Confusing set operations with arithmetic operations
This explanation was generated by AI. While we work hard to be accurate, mistakes can happen! Always double-check important answers with your teacher or textbook.

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Solve: 2x + 5 = 13
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Subtract 5 from both sides...
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