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Determine the algebraic inverse function by swapping x and y and solving for y | Step-by-Step Solution

MathAlgebra - Function Inverses
Explained on January 19, 2026
📚 Grade college🟡 Medium⏱️ 15-20 min

Problem

Find the inverse of y = ln(ln(x-3)) + 1

🎯 What You'll Learn

  • Understand how to find inverse functions
  • Practice manipulating logarithmic expressions
  • Develop algebraic problem-solving skills

Prerequisites: logarithm properties, function transformations, algebraic substitution

💡 Quick Summary

Hi there! I can see you're working with finding an inverse function, which is a really important skill in algebra. This problem involves a composition of natural logarithms, so you'll need to think about how to "undo" these operations step by step. When you swap x and y, what operations do you see that were applied to the original input, and in what order? Here's a key insight to consider: if you want to undo a natural logarithm, what function would you use, and how might you apply this principle when you have logarithms nested inside each other? Try starting by isolating the outermost operation first, then work your way inward - think of it like peeling an onion! You've got the right approach with swapping x and y, so now it's just a matter of carefully undoing each step.

Step-by-Step Explanation

Finding the Inverse Function

What We're Solving:

We need to find the inverse of y = ln(ln(x-3)) + 1. This means we want to find a function that "undoes" what our original function does to any input value.

The Approach:

To find an inverse function, we use the "swap and solve" method:
  • 1. Swap x and y in our equation
  • 2. Solve the new equation for y
  • 3. The result is our inverse function f⁻¹(x)
If our original function takes some input and transforms it through a series of steps, the inverse function does those same steps backwards to get us back to where we started!

Step-by-Step Solution:

Step 1: Write our original equation y = ln(ln(x-3)) + 1

Step 2: Swap x and y x = ln(ln(y-3)) + 1

Now we need to solve for y. We'll "peel away" each operation, working from the outside in!

Step 3: Isolate the first natural logarithm x - 1 = ln(ln(y-3)) (We subtracted 1 from both sides)

Step 4: Use the exponential function to "undo" the outer ln e^(x-1) = ln(y-3) (Since e^(ln(something)) = something)

Step 5: Use the exponential function again to "undo" the inner ln e^(e^(x-1)) = y-3 (Same principle: e^(ln(something)) = something)

Step 6: Solve for y y = e^(e^(x-1)) + 3 (We added 3 to both sides)

The Answer:

The inverse function is: f⁻¹(x) = e^(e^(x-1)) + 3

Memory Tip:

Think of inverse functions like getting dressed and undressed! If you put on socks, then shoes, then a coat, you'd take them off in reverse order: coat, shoes, then socks.

Our original function: subtract 3, take ln, take ln again, then add 1 Our inverse function: subtract 1, take e^x, take e^x again, then add 3

The operations are reversed AND in opposite order! 🧦👟🧥

Great job working through this challenging composite function! The key is patience and working step-by-step to "undo" each operation.

⚠️ Common Mistakes to Avoid

  • Incorrectly swapping x and y
  • Failing to solve for the final inverse expression
  • Not checking domain and range restrictions

This explanation was generated by AI. While we work hard to be accurate, mistakes can happen! Always double-check important answers with your teacher or textbook.

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📷 Problem detected:

Solve: 2x + 5 = 13

Step 1:

Subtract 5 from both sides...

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