Find the asymptotic expansion of a sum involving fractional parts for a real power α as x approaches infinity | Step-by-Step Solution
Problem
Asymptotic expansion of sum of fractional parts for real power α
🎯 What You'll Learn
- Understand asymptotic behavior of summation with fractional parts
- Apply generalized limit techniques
- Analyze summation methods for non-integer powers
Prerequisites: Advanced calculus, Limit theory, Zeta function properties
💡 Quick Summary
I see you're working with a sum involving fractional parts of powers - this is a beautiful problem that combines number theory with asymptotic analysis! The key insight here is to think about what the fractional part function $\{y\} = y - \lfloor y \rfloor$ is actually doing to each term in your sum. Have you considered how you might split this sum by using the definition of fractional parts, and what tools you know for handling sums of powers versus sums involving floor functions? Also, think about whether it matters if α is rational or irrational - does the behavior of the sequence $\{n^α\}$ change in these different cases? I'd encourage you to look into the Euler-Maclaurin formula for handling the power sum part, and consider concepts like equidistribution for understanding how the fractional parts behave. You've got the mathematical tools to tackle this step by step - start by breaking down what each piece of the sum is doing!
Step-by-Step Explanation
What We're Solving:
We're looking at sums of the form $\sum_{n=1}^{x} \{n^{\alpha}\}$ where $\{y\}$ denotes the fractional part of $y$ (i.e., $\{y\} = y - \lfloor y \rfloor$), and we want to find how this sum behaves as $x \to \infty$.The Approach:
The key insight is to use the Euler-Maclaurin formula combined with properties of fractional parts:- Fractional parts are periodic-like functions that oscillate between 0 and 1
- The Euler-Maclaurin formula helps us convert discrete sums into integrals plus correction terms
- For irrational α, we get different behavior than for rational α due to distribution properties
Step-by-Step Solution:
Step 1: Rewrite using fractional part identity Start with $\{y\} = y - \lfloor y \rfloor$, so: $$\sum_{n=1}^{x} \{n^{\alpha}\} = \sum_{n=1}^{x} n^{\alpha} - \sum_{n=1}^{x} \lfloor n^{\alpha} \rfloor$$
Step 2: Handle the first sum The sum $\sum_{n=1}^{x} n^{\alpha}$ has a known asymptotic expansion:
- If α > -1: $\sum_{n=1}^{x} n^{\alpha} = \frac{x^{\alpha+1}}{\alpha+1} + \frac{x^{\alpha}}{2} + O(x^{\alpha-1})$
- For irrational α: Use Weyl's equidistribution theorem
- For rational α = p/q: The fractional parts have period q, leading to different asymptotics
The Framework:
Here's the general result structure:For irrational α > 0: $$\sum_{n=1}^{x} \{n^{\alpha}\} = \frac{x}{2} + O(x^{\theta})$$ where θ < 1 depends on α.
For rational α = p/q with gcd(p,q) = 1: The expansion involves periodic terms and the structure is more complex.
Memory Tip:
Think of fractional parts as "cutting off the integer part" - they measure how far each $n^{\alpha}$ is above its floor. For irrational powers, these fractional parts spread out evenly (equidistribution), giving us the clean asymptotic behavior. The key is always: integer part + fractional part = whole number, so study each piece separately!⚠️ Common Mistakes to Avoid
- Assuming integer power techniques apply directly to real powers
- Neglecting error bounds in asymptotic expansions
- Misinterpreting floor function approximations
This explanation was generated by AI. While we work hard to be accurate, mistakes can happen! Always double-check important answers with your teacher or textbook.

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📷 Problem detected:
Solve: 2x + 5 = 13
Step 1:
Subtract 5 from both sides...
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