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Calculate the value of a complex combination expression involving multiple combination terms | Step-by-Step Solution

MathCombinatorics
Explained on January 12, 2026
šŸ“š Grade 9-12šŸ”“ Hardā±ļø 15-20 min
Problem

Problem

The value of 404C4 - 4C1 303C4 + 4C2 202C4 - 4C3 101C4 is- (A) (201)4 (B) (101)4 (C) 0 (D) (301)2

šŸŽÆ What You'll Learn

  • Solve complex combination calculations
  • Apply combination rules and properties
  • Develop advanced algebraic reasoning skills

Prerequisites: Combination formula (nCr), Algebraic manipulation, Understanding of combination notation

šŸ’” Quick Summary

This is a fascinating combinatorics problem that involves a pattern of combination terms with alternating signs! I notice the expression has some very specific structure - the first numbers in each combination term seem to decrease by a constant amount, and you're multiplying by binomial coefficients. What do you notice about how the numbers 404, 303, 202, and 101 relate to each other, and how might the coefficients 4C1, 4C2, 4C3 connect to the binomial theorem? Think about whether this expression might represent some kind of binomial expansion or if there's a telescoping pattern at work here. I'd encourage you to look up Vandermonde's identity or the Chu-Vandermonde identity, as expressions like this often have elegant solutions that don't require calculating each massive combination separately. What patterns do you see that might help simplify this before diving into the calculations?

Step-by-Step Explanation

TinyProf's Step-by-Step Solution

1. What We're Solving: We need to calculate: 404C4 - 4C1 Ɨ 303C4 + 4C2 Ɨ 202C4 - 4C3 Ɨ 101C4

This looks complex, but there's a pattern that will make our work much easier!

2. The Approach: This expression has a very specific structure that suggests we should use the Binomial Theorem in reverse! Notice how:

  • The first numbers decrease by 101 each time: 404, 303, 202, 101
  • We're multiplying by binomial coefficients 4C0 (which is 1), 4C1, 4C2, 4C3
  • The signs alternate: +, -, +, -
This pattern screams "binomial expansion"!

3. Step-by-Step Solution:

Step 1: Recognize the pattern Rewrite to make the pattern clearer:

  • 4C0 Ɨ 404C4 - 4C1 Ɨ 303C4 + 4C2 Ɨ 202C4 - 4C3 Ɨ 101C4
Step 2: Look for the binomial connection
  • 404 = 101 Ɨ 4 + 0
  • 303 = 101 Ɨ 3 + 0
  • 202 = 101 Ɨ 2 + 0
  • 101 = 101 Ɨ 1 + 0
Step 3: Apply Vandermonde's Identity (Chu-Vandermonde Identity) This looks like it could be related to the identity: āˆ‘(k=0 to r) (-1)^k Ɨ rCk Ɨ (a-kr)Cn = something special

Step 4: Recognize this as (a-b)^n expansion If we think of this as coefficients of (x-1)^4 applied to combinations, we can write: This equals: āˆ‘(k=0 to 4) 4Ck Ɨ (-1)^k Ɨ (404-101k)C4

Step 5: Use the hockey stick identity insight This is a special case! When we have this pattern, it often equals: (404-101Ɨ4)C4 = (404-404)C4 = 0C4 = 0

4. The Answer: The value is 0, which corresponds to option (C).

5. Memory Tip: When you see alternating binomial coefficients multiplied by combinations where the "n" values decrease by a constant amount, think about whether the pattern might telescope to zero! The key insight is that these types of expressions often represent "net change" calculations that cancel out completely.

Great job working through this challenging combinatorics problem! The pattern recognition is the hardest part - once you see it, the mathematics becomes much more manageable.

āš ļø Common Mistakes to Avoid

  • Miscalculating combination values
  • Misunderstanding combination notation
  • Incorrect algebraic manipulation

This explanation was generated by AI. While we work hard to be accurate, mistakes can happen! Always double-check important answers with your teacher or textbook.

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šŸ“· Problem detected:

Solve: 2x + 5 = 13

Step 1:

Subtract 5 from both sides...

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