Find a solution to the Laplace equation in cylindrical coordinates with specific boundary conditions on a half-infinite cylinder | Step-by-Step Solution
Problem
Solving Laplace equation outside a half-infinite cylinder using cylindrical coordinates. Problem involves finding u(r,θ,z) satisfying ∇²u = 0 with specific boundary conditions on a cylindrical domain.
🎯 What You'll Learn
- Apply variable separation method to solve PDEs
- Understand boundary conditions in cylindrical coordinates
- Analyze solutions to Laplace equation
Prerequisites: Advanced calculus, Differential equations, Bessel functions
💡 Quick Summary
Hi there! I can see you're working with the Laplace equation in cylindrical coordinates - this is a beautiful problem that combines partial differential equations with special functions. The key insight here is that when you have cylindrical geometry, separation of variables becomes your best friend because it breaks this complex 3D problem into three manageable 1D problems. Have you thought about what happens when you assume a solution of the form u(r,θ,z) = R(r)Θ(θ)Z(z) and substitute it back into the Laplace equation? Also, consider what the boundary conditions tell you about the behavior of your solution - do you need it to be bounded as certain variables approach infinity? I'd encourage you to start by writing out Laplace's equation in cylindrical coordinates and then try the separation of variables approach, keeping in mind that the r-equation will lead you to a very special and important family of functions. You've got the right mathematical tools to tackle this step by step!
Step-by-Step Explanation
🌟 Solving the Laplace Equation
1. What We're Solving:
We need to find a function u(r,θ,z) that satisfies Laplace's equation ∇²u = 0 in cylindrical coordinates, specifically outside a half-infinite cylinder (r > a, z > 0) with given boundary conditions. This is a classic problem in mathematical physics!2. The Approach:
We'll use the separation of variables method because:- Cylindrical coordinates are perfect for cylindrical geometry
- The linearity of Laplace's equation allows us to build solutions from simpler parts
- We can match our general solution to the specific boundary conditions
3. Step-by-Step Solution:
Step 1: Set up the equation in cylindrical coordinates ∇²u = (1/r)(∂/∂r)(r∂u/∂r) + (1/r²)(∂²u/∂θ²) + ∂²u/∂z² = 0
Step 2: Assume separated solution Let u(r,θ,z) = R(r)Θ(θ)Z(z)
Step 3: Substitute and separate After substituting and dividing by RΘZ:
- (1/r)(d/dr)(r dR/dr)/R + (1/r²)(d²Θ/dθ²)/Θ + (d²Z/dz²)/Z = 0
- r(d/dr)(r dR/dr)/R + (d²Θ/dθ²)/Θ + r²(d²Z/dz²)/Z = 0
- d²Z/dz² = k²Z (choose k² for exponential solutions in z)
- d²Θ/dθ² = -n²Θ (choose -n² for periodic solutions in θ)
- r(d/dr)(r dR/dr) = (k²r² + n²)R
For Z(z): Z(z) = A₁e^(kz) + A₂e^(-kz)
For Θ(θ): Θ(θ) = B₁cos(nθ) + B₂sin(nθ)
For R(r): This gives us Bessel's equation!
- If k ≠ 0: R(r) = C₁I_n(kr) + C₂K_n(kr)
- If k = 0: R(r) = C₃r^n + C₄r^(-n)
- Use boundedness conditions (u must not blow up as r→∞ or z→∞)
- Apply the given boundary values
- Use orthogonality to find coefficients
4. The General Framework:
Your final solution will typically look like:u(r,θ,z) = Σ[A_n K_n(k_n r)(B_n cos(nθ) + C_n sin(nθ))e^(-k_n z)]
The specific coefficients A_n, B_n, C_n and values k_n depend on your exact boundary conditions!
5. Memory Tip: 🎯
Remember "SBC" - Separate variables, solve the Bessel equation for r, then apply Conditions!The key insight is that problems with cylindrical symmetry naturally lead to Bessel functions - they're the "sine and cosine" of cylindrical coordinates!
⚠️ Common Mistakes to Avoid
- Mishandling boundary conditions
- Incorrect application of variable separation
- Misunderstanding special functions like Bessel functions
This explanation was generated by AI. While we work hard to be accurate, mistakes can happen! Always double-check important answers with your teacher or textbook.

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📷 Problem detected:
Solve: 2x + 5 = 13
Step 1:
Subtract 5 from both sides...
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