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Demonstrate how to prove convergence in distribution when moment generating functions converge in a specified interval | Step-by-Step Solution

MathProbability Theory
Explained on January 12, 2026
๐Ÿ“š Grade graduate๐Ÿ”ด Hardโฑ๏ธ 1+ hour

Problem

Proof of convergence in distribution using Prokhorov's theorem and uniqueness of moment generating functions (MGFs)

๐ŸŽฏ What You'll Learn

  • Understand proof techniques for distribution convergence
  • Apply Prokhorov's theorem in probability proofs
  • Analyze moment generating function properties

Prerequisites: Advanced probability theory, Measure theory fundamentals, Convergence concepts

๐Ÿ’ก Quick Summary

Hi there! I can see you're working with a really elegant convergence problem that sits at the intersection of probability theory and analysis. This is essentially about showing that when moment generating functions converge pointwise in a neighborhood of zero, the underlying random variables must converge in distribution - but how might you bridge that gap? Think about what obstacles typically prevent a sequence from converging: the sequence could have subsequences wandering off to different limits, or the probability mass could be "escaping to infinity." What theorems do you know that could help control each of these issues separately? Consider how Prokhorov's theorem handles tightness and subsequential convergence, and then think about what the uniqueness property of MGFs tells you about potential limit points. The beautiful thing is that you can use a classic "compactness plus uniqueness" argument here - try approaching this in two stages where you first ensure some subsequence converges, then show that all possible limits must be the same!

Step-by-Step Explanation

Hi there! This is a beautiful and sophisticated problem in probability theory. Let's break it down together so you can really understand how these powerful theorems work together.

What We're Solving:

We want to understand how to prove that a sequence of random variables converges in distribution by using two key tools: Prokhorov's theorem (which helps us find convergent subsequences) and the uniqueness property of moment generating functions (which helps us identify what we're converging to).

The Approach:

  • Stage 1 (Prokhorov): We use Prokhorov's theorem to guarantee that some subsequence converges in distribution
  • Stage 2 (MGF Uniqueness): We use the uniqueness of MGFs to prove that all possible limit points are the same, which means the entire sequence converges
This is a classic "compactness + uniqueness = convergence" argument that appears throughout mathematics!

Step-by-Step Solution:

Step 1: Set up the problem framework Let {Xโ‚™} be a sequence of random variables with moment generating functions Mโ‚™(t). Assume:

  • Mโ‚™(t) โ†’ M(t) for all t โˆˆ (-ฮด, ฮด) for some ฮด > 0
  • M(t) is the MGF of some random variable X
Step 2: Apply Prokhorov's theorem (the compactness part)
  • First, we need to show the sequence {Xโ‚™} is tight (the probability mass doesn't "escape to infinity")
  • Since MGFs converge in a neighborhood of 0, we can show moments are bounded
  • Bounded moments imply tightness (this takes a bit of work with Chebyshev's inequality)
  • By Prokhorov's theorem: every subsequence has a further subsequence that converges in distribution
Step 3: Identify what subsequences converge to (the uniqueness part)
  • Take any convergent subsequence Xโ‚™โ‚– โ‡’ Y (convergence in distribution)
  • By the continuity theorem for MGFs: Mโ‚™โ‚–(t) โ†’ Mแตง(t) in a neighborhood of 0
  • But we also know Mโ‚™โ‚–(t) โ†’ M(t) since it's a subsequence of our original sequence
  • Therefore: Mแตง(t) = M(t) in a neighborhood of 0
Step 4: Apply MGF uniqueness
  • Since MGFs uniquely determine distributions (when they exist in a neighborhood of 0)
  • We conclude Y has the same distribution as X
  • This means every convergent subsequence converges to the same limit!
Step 5: Conclude full sequence convergence
  • Every subsequence has a further subsequence converging to X
  • All convergent subsequences have the same limit
  • This is equivalent to the entire sequence converging: Xโ‚™ โ‡’ X

The Answer:

Theorem: If {Xโ‚™} is a sequence of random variables with MGFs Mโ‚™(t) such that Mโ‚™(t) โ†’ M(t) for all t in some interval (-ฮด, ฮด), and M(t) is the MGF of a random variable X, then Xโ‚™ โ‡’ X.

Proof Structure:

  • 1. Use MGF convergence to establish tightness
  • 2. Apply Prokhorov to get subsequential compactness
  • 3. Use MGF uniqueness to show all limit points are identical
  • 4. Conclude full sequence convergence

Memory Tip:

Remember this as the "Squeeze Play" theorem! ๐Ÿ“
  • Prokhorov squeezes the sequence into a compact space (preventing escape to infinity)
  • MGF uniqueness squeezes all possible limits into a single point
  • Together, they squeeze the entire sequence to converge to one limit!
The key insight is that we're combining a topological tool (compactness) with an analytical tool (uniqueness) to get a powerful convergence result. This pattern appears in many areas of analysis - it's worth remembering!

โš ๏ธ Common Mistakes to Avoid

  • Misunderstanding tightness conditions
  • Confusing different types of convergence
  • Incorrectly applying MGF uniqueness theorem

This explanation was generated by AI. While we work hard to be accurate, mistakes can happen! Always double-check important answers with your teacher or textbook.

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Solve: 2x + 5 = 13

Step 1:

Subtract 5 from both sides...

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