Investigate whether the quotient of a locally compact space is always locally compact | Step-by-Step Solution
Problem
Is every quotient from a locally compact space locally compact? The author provides a reasoning that the image of compact sets is compact under a continuous function, and that a continuous image of a basis is a basis. However, they note a counterexample: โ is locally compact, but โ quotiented by โค is not locally compact.
๐ฏ What You'll Learn
- Understand properties of quotient spaces
- Analyze preservation of topological properties under quotient mappings
- Develop critical thinking in topological reasoning
Prerequisites: point-set topology, continuous function theory, set theory
๐ก Quick Summary
This is a fantastic topology question about how nice properties behave under quotient maps! You're right to be skeptical of that initial reasoning - while it's true that continuous maps preserve compactness, there's a subtle but crucial flaw in the logic about bases. Can you think about what it really means for a space to be locally compact in terms of neighborhoods around each point, and whether the quotient topology might disrupt that local structure even if compact sets stay compact? I'd encourage you to consider some concrete examples - maybe think about what happens when you take a familiar locally compact space like the real line and create a quotient that dramatically changes the topology. The key insight here is distinguishing between global properties (like preserving compactness of sets) versus local properties (like having the right kind of neighborhood structure around each point). Give it another shot with these ideas in mind - you're definitely on the right track with your critical thinking!
Step-by-Step Explanation
TinyProf's Guide to Quotient Spaces and Local Compactness
What We're Solving: We need to determine whether quotient spaces preserve local compactness - that is, if we start with a locally compact space and create a quotient space, will the result always be locally compact?
The Approach: This is a great example of mathematical reasoning! We'll examine the general principles, analyze why the initial reasoning seems plausible, then carefully check the counterexample to see what's really happening.
Step-by-Step Solution:
Step 1: Understand the Initial Reasoning The reasoning provided has some truth to it:
- โ Continuous maps do preserve compactness (compact sets map to compact sets)
- โ However, "the continuous image of a basis is a basis" is not generally true!
Step 2: Recall What Local Compactness Means A space X is locally compact if every point has a neighborhood base consisting of compact sets. Equivalently, every point has a compact neighborhood.
Step 3: Analyze the Counterexample โ/โค The circle โ/โค is homeomorphic to the unit circle Sยน, which is compact and locally compact.
Step 4: Find a True Counterexample Here's a classic counterexample:
- Take X = โยฒ (which is locally compact)
- Consider the equivalence relation that identifies all points on each line y = n (for integer n)
- The quotient space X/~ is not locally compact
Step 5: A Cleaner Counterexample An even simpler example:
- Take the locally compact space โ
- Consider the quotient map that sends โ to โ โช {โ} but with the indiscrete topology on the image
- This quotient is not locally compact because no point has a compact neighborhood in the indiscrete topology.
Memory Tip: Remember: "Quotients can be quotient!" - meaning they can lose nice properties. Continuous maps preserve compactness globally, but quotient topology can mess up the local neighborhood structure that makes local compactness work.
Great job thinking through this problem and questioning the initial reasoning - that's exactly the kind of critical thinking that makes you a strong mathematician! ๐
โ ๏ธ Common Mistakes to Avoid
- Assuming all topological properties are preserved under quotient mappings
- Incorrectly generalizing properties of continuous functions
- Not rigorously verifying topological conditions
This explanation was generated by AI. While we work hard to be accurate, mistakes can happen! Always double-check important answers with your teacher or textbook.

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๐ท Problem detected:
Solve: 2x + 5 = 13
Step 1:
Subtract 5 from both sides...
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