Calculate the inclination angle of a line given its slope using inverse tangent and angle calculation | Step-by-Step Solution
Problem
A line with a slope of -1/√3 is given. Find its inclination (angle with the positive x-axis measured anticlockwise).
🎯 What You'll Learn
- Calculate line inclination from slope
- Understand relationship between slope and angle
- Apply inverse tangent function to find angle
Prerequisites: trigonometric functions, slope calculation, inverse trigonometric functions
💡 Quick Summary
Hi there! I can see you're working on finding the inclination angle of a line when you know its slope - this is a fantastic problem that connects trigonometry with coordinate geometry! The key insight here is remembering the fundamental relationship between a line's slope and the tangent of its inclination angle. Since you have a negative slope of -1/√3, what do you think this tells you about which quadrant your inclination angle should be in, and how might you use inverse tangent to find it? I'd encourage you to think about what angle has a tangent of 1/√3 first (the positive version), and then consider how the negative sign affects where your final angle lands when measuring counterclockwise from the positive x-axis. You've got all the tools you need - trust your understanding of the unit circle and inverse trig functions!
Step-by-Step Explanation
🌟 Understanding Line Inclination from Slope
1. What We're Solving:
We need to find the inclination angle (the angle a line makes with the positive x-axis, measured counterclockwise) when we know the line has a slope of -1/√3.2. The Approach:
The key relationship is that slope = tan(θ), where θ is the inclination angle. Since we know the slope, we can use the inverse tangent (arctan) to find the angle. We need to be careful about which quadrant our angle should be in, since slopes can be negative!3. Step-by-Step Solution:
Step 1: Set up the relationship
- We know: slope = -1/√3
- We use: slope = tan(θ)
- So: tan(θ) = -1/√3
- First, find what angle has tangent = 1/√3 (the positive version)
- tan⁻¹(1/√3) = 30° (or π/6 radians)
- This is our reference angle!
- Since our slope is NEGATIVE (-1/√3), our line is falling from left to right
- For inclination angles (measured counterclockwise from positive x-axis), negative slopes correspond to angles in the second quadrant (between 90° and 180°)
- In the second quadrant: θ = 180° - 30° = 150°
- Or in radians: θ = π - π/6 = 5π/6 radians
- Let's check: tan(150°) = tan(180° - 30°) = -tan(30°) = -1/√3 ✓
- Perfect! This matches our given slope.
4. The Answer:
The inclination angle is 150° (or 5π/6 radians).5. Memory Tip:
Remember the "Slope-Angle Dance":- Positive slope → angle between 0° and 90° (line going upward)
- Negative slope → angle between 90° and 180° (line going downward)
- The reference angle (30° in this case) helps you find exactly where in that range you land!
⚠️ Common Mistakes to Avoid
- Confusing slope and inclination angle
- Incorrectly applying inverse tangent function
- Misinterpreting the range of angle measurement
This explanation was generated by AI. While we work hard to be accurate, mistakes can happen! Always double-check important answers with your teacher or textbook.

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Solve: 2x + 5 = 13
Step 1:
Subtract 5 from both sides...
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